8(sin^2)x+4(cos^2)x=7

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Solution for 8(sin^2)x+4(cos^2)x=7 equation: 


Simplifying
8(sin2) * x + 4(cos2) * x = 7

Multiply in2s * x
8in2sx + 4(cos2) * x = 7

Multiply cos2 * x
8in2sx + 4cos2x = 7

Reorder the terms:
4cos2x + 8in2sx = 7

Solving
4cos2x + 8in2sx = 7

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8in2sx' to each side of the equation.
4cos2x + 8in2sx + -8in2sx = 7 + -8in2sx

Combine like terms: 8in2sx + -8in2sx = 0
4cos2x + 0 = 7 + -8in2sx
4cos2x = 7 + -8in2sx

Divide each side by '4os2x'.
c = 1.75o-1s-2x-1 + -2in2o-1s-1

Simplifying
c = 1.75o-1s-2x-1 + -2in2o-1s-1

Reorder the terms:
c = -2in2o-1s-1 + 1.75o-1s-2x-1

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